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9*2^2x=576
We move all terms to the left:
9*2^2x-(576)=0
Wy multiply elements
18x^2-576=0
a = 18; b = 0; c = -576;
Δ = b2-4ac
Δ = 02-4·18·(-576)
Δ = 41472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{41472}=\sqrt{20736*2}=\sqrt{20736}*\sqrt{2}=144\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144\sqrt{2}}{2*18}=\frac{0-144\sqrt{2}}{36} =-\frac{144\sqrt{2}}{36} =-4\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144\sqrt{2}}{2*18}=\frac{0+144\sqrt{2}}{36} =\frac{144\sqrt{2}}{36} =4\sqrt{2} $
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